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channels: Use the UU playlist to get videos by default

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This will be much less likely to break moving forward since
YouTube rarely changes the playlist api

Videos page now includes shorts and streams in the video lsit

Also include an option to filter out shorts on the videos page
This commit is contained in:
Astound
2024-01-22 05:39:11 +08:00
parent d591956baa
commit b45e3476c8
3 changed files with 100 additions and 47 deletions
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30
youtube/playlist.py
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@@ -47,23 +47,25 @@ def playlist_first_page(playlist_id, report_text="Retrieved playlist", use_mobil
return content
def get_videos(playlist_id, page, use_mobile=False):
def get_videos(playlist_id, page, include_shorts=True, use_mobile=False):
# mobile requests return 20 videos per page
if use_mobile:
url = "https://m.youtube.com/playlist?ctoken="
url += playlist_ctoken(playlist_id, (int(page)-1)*20) + "&pbj=1"
content = util.fetch_url(
url, util.mobile_xhr_headers,
report_text="Retrieved playlist", debug_name='playlist_videos'
)
page_size = 20
headers = util.mobile_xhr_headers
# desktop requests return 100 videos per page
else:
url = "https://www.youtube.com/playlist?ctoken="
url += playlist_ctoken(playlist_id, (int(page)-1)*100) + "&pbj=1"
content = util.fetch_url(
url, util.desktop_xhr_headers,
report_text="Retrieved playlist", debug_name='playlist_videos'
)
page_size = 100
headers = util.desktop_xhr_headers
url = "https://m.youtube.com/playlist?ctoken="
url += playlist_ctoken(playlist_id, (int(page)-1)*page_size,
include_shorts=include_shorts)
url += "&pbj=1"
content = util.fetch_url(
url, headers, report_text="Retrieved playlist",
debug_name='playlist_videos'
)
info = json.loads(content.decode('utf-8'))
return info
@@ -117,7 +119,7 @@ def get_playlist_page():
'playlist.html',
header_playlist_names=local_playlist.get_playlist_names(),
video_list=info.get('items', []),
num_pages = math.ceil(video_count/100),
num_pages=math.ceil(video_count/100),
parameters_dictionary=request.args,
**info['metadata']